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I have the numbers 6, 30, 8, 8, 3, 7, 1, 2, and 5. Using only addition, subtraction, and multiplication, can you use those numbers to make 60, 54, and 52?

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  • $\begingroup$ Do I have to use all numbers provided? $\endgroup$ – user175968 Oct 14 '14 at 11:25
  • $\begingroup$ And can one only use each number once? $\endgroup$ – AmagicalFishy Oct 14 '14 at 11:25
  • $\begingroup$ Can you clarify this question please. Are you saying write three equations using the above numbers using addition, subtraction and multiplication only to give 60, 54 and 52 using each number no more than once across all three equations or using each number exactly once? $\endgroup$ – Warren Hill Oct 14 '14 at 11:40
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$$6+30+8+8+3+7+1+2\color{red}{-}5=60.$$ $$6+30+8+8\color{red}{-}3+7+1+2\color{red}{-}5=54.$$ $$6+30+8+8\color{red}{-}3+7\color{red}{-}1+2\color{red}{-}5=52.$$

P.S. $$30\times 2=60.$$ $$6\times (8+1)=54.$$ $$(8+5)\times (7-3)=52.$$

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  • $\begingroup$ oh, my mistake, I didn't mention, you can only use the numbers once. So for instance, if you use 30x2=60, you only have the remaining numbers to make up 54 and 52. $\endgroup$ – Greg Oct 14 '14 at 11:29
  • $\begingroup$ There's a chance it isn't possilbe. It's for a silly math game on my phone and it's wrecking my brain. $\endgroup$ – Greg Oct 14 '14 at 11:30
  • $\begingroup$ @Greg at most once or exactly once? $\endgroup$ – Coolwater Oct 14 '14 at 11:32
  • $\begingroup$ Yeah you can only use each number once to get all 3 numbers.. like I said, it may not be possible. $\endgroup$ – Greg Oct 14 '14 at 11:34
  • $\begingroup$ @Greg: I added a bit. How about that? $\endgroup$ – mathlove Oct 14 '14 at 11:35

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