# Find tangent line at given points, no function equation

I have never encountered a problem like this and am a bit confused.

Function $f$ satisfies:

$f(3)=5$, $f(9)=7$

$f'(3)=11$, $f'(9)=13$

Find an equation for the tangent line to the curve $y=f(x^2)$ at point $(x,y) = (3,7)$.

I don't know where to start. I drew a graph of the points related to the slope of the derivative but that doesn't really help me, and I don't understand the concept of $y = f(x^2)$.

A point in the right direction would be great, thank you for any help!

Hint 1: By the Chain Rule, we have $\frac{dy}{dx}=(2x)f'(x^2)$.
Hint 2: The information about $f(3)$ and $f'(3)$ is meant to lead you astray. Not nice!