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I have a few doubts regarding vectors and linear algebra in general:

  1. What is the formal definition of a vector?
  2. When we say $\Bbb R^n$, do we mean the set of all column matrices with $n$ entries,or all row matrices with n entries, or all ordered $n$ tuples that is $(a_1,.....,a_n)$ ?
  3. If all members of a vector space are vectors, since $\Bbb R$ is a vector space, then it is implied that all real numbers are vectors. Is my understanding correct ?
  4. Geometrically, can we treat vectors as free or fixed? What is the correct convention?
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  • $\begingroup$ Real numbers are single component vectors. $\endgroup$ Oct 6, 2014 at 19:37

2 Answers 2

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  1. A vector is an element of a vector space

  2. We usually mean ordered $n$ tuples .Though, we sometimes want the other descriptions- depending upon the context. All these spaces are naturally isomorphic (as vector spaces).

  3. Real numbers are definitely vectors- as they are members of a $1$ dimensional vector space.

  4. We usually treat vectors as "fixed". For example, the vector $(1,0)$ in $\mathbb{R^2}$ can be pictured as a vector whose "tip" is the point $(1,0)$ and "tail" is the point $(0,0)$.

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  • $\begingroup$ voldemort, when you say "usually treat", what do you mean? Is the convention flexible? Also, I have an intuitive grasp of what isomorphic means, but as I am a first year undergrad, could you please give me a rigorous definition? $\endgroup$
    – Student
    Oct 6, 2014 at 19:11
  • $\begingroup$ It does not really matter if you write down the vector as a row or column, this is just a notation which do vary a lot depending on the teacher, but the object itself is the same, the notation is just a way of representing the object. You could even write down a vector in different polar forms but the object is still the same. I'd like to add that I do not like the terms of free and fixed since a vector is everywhere but the arrows we all like to draw as visualization is just another representation but not the object itself! $\endgroup$
    – flawr
    Oct 6, 2014 at 19:13
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    $\begingroup$ Usually treat means that in most contexts this is the meaning you would find. In math sometimes some people use a different convention- and to be safe I use the term "usually treat". Isomorphic means they have the same structure as vector spaces- i.e. there exists a one-one, onto linear map which is invertible between the two spaces. $\endgroup$
    – voldemort
    Oct 6, 2014 at 19:13
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    $\begingroup$ @flawr: Exactly- the spaces are isomorphic. Most people that I know prefer to think $\mathbb{R^n}$ as $n$ tuples, but the other two approaches are the same anyway. $\endgroup$
    – voldemort
    Oct 6, 2014 at 19:14
  • $\begingroup$ @flawr: Hmmmm aren't the 2 objects different? For instance, you cannot say that a 2-by-1 matrix is the same as a 1-by-2 matrix, can you? Voldemort's way of explaining it seems to make sense, as he acknowledges the isomorphism between the two spaces, but considers them as different objects. $\endgroup$
    – Student
    Oct 6, 2014 at 19:19
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  1. We say "vector" instead of "element of a vector space", especially by tradition in lessons on abstract vector spaces. We could also say "point", or "chair" if we wished.
  2. When we say $\mathbb{R}^n$, we mean $n$-tuples.
  3. Your understanding is correct, if you agree with my point n°1.
  4. Geometrically, let us place ourselves in $\mathbb{R}^2$, "the plane": on your drawing, you can interpret the elements of $\mathbb{R}^2$ as you wish, as long as it makes sense. For me, I can represent $(2,3)$ by a point $A$, "point $A$ with coordinates $2$ and $3$". If I am interested in the line $D$ of equation $y=5-x$, for example because it is the tangent to the function $f:\mathbb{R} \to \mathbb{R}, x\mapsto 3-\sin(x-2)$ at A, I will more naturally talk about $(1,-1)$ as the vector $u=(1,-1)$, which is a directing vector of $D$. About $D$ I will say that it is the affine line of $\mathbb{R}^2$, $D=A+\mathbb{R}.u$, and I will obviously conceive of it as a set of points. And i will conceive $\mathbb{R}u$ as the vector line passing through $u$.
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