0
$\begingroup$

Question:

Find the closed form of

$$I(x,y)=\int_{0}^{1}t^{-1/2}\left(1-\dfrac{t}{1+4y}\right)^{-1/2-ix}dt$$

where $i^2=-1$

I have used Wolfram Alpha but it can't help me out. How to find it?

Thank you


I have explained why I can't comment, because in China we can't comment in MSE, (I don't know why?) Now, I can only post questions and I also can answer questions , but I can't comment.

china math110 also said that he can't comment. Here is the proof: How find all positive real $\beta$ such A finite number of $\left|\frac{p}{q}-\sqrt{2}\right|<\frac{\beta}{q^2}$

How prove $f(a_{i})=0$ if $\int_{0}^{1}x^kf(x)dx=0,k=1,2,3,\cdots,n$

$\endgroup$
  • $\begingroup$ Mr. @CameronWilliams, I can understand if he doesn't wanna interact with those that comment and answer china math's problem. Don't be so harsh about that ツ $\endgroup$ – Anastasiya-Romanova 秀 Oct 5 '14 at 15:47
  • $\begingroup$ wolf can't help - Yeah... wolves never do... :-( $\endgroup$ – Lucian Oct 5 '14 at 15:52
1
$\begingroup$

If your x and y are independent of t, then the answer is simply an incomplete beta function.

$\endgroup$

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.