I want to find the probability that in a deck of only face cards (jacks, queens, kings, each with their standard 4 suits), you draw exactly 2 queens and exactly 2 kings. Only 4 cards are being drawn.
Also, the same question again but where each queen has a king of the same matching suit. I was thinking we use counting for this so would the first one just be 5 divided by 13 choose 4? Where 5 is the permutations of the four cards (2 queens and 2 kings). For the second I am not so sure, any pointers?