# Can $\sqrt{a}^\sqrt{b}$ be rational if $\sqrt{a}$ and $\sqrt{b}$ are irrational?

Let $$a$$ and $$b$$ be rational numbers, such that $$\sqrt{a}$$ and $$\sqrt{b}$$ are irrational.

Can $$\sqrt{a}^\sqrt{b}$$ be rational?

I found examples, where the irrational power of an irrational number is rational, but in those examples at least one of those numbers (base and exponent) has not been a square root of a rational.

Since ${\sqrt{a}}^{\sqrt{b}}$ is expressed as an algebraic number not equal to $0$ or $1$ raised to an irrational algebraic power, the result will be transcendental (and hence irrational) by the Gelfond–Schneider theorem.