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How do I change the subject of the equation below to $b$?

$$a = \frac{k}{2b + 4c}$$

I'm getting nowhere with this one.

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  • $\begingroup$ Welcome to the Math StackExchange. What have you tried? $\endgroup$ – Paul Sundheim Oct 1 '14 at 20:40
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rearrange in a few steps: $$2ab+4ac=k$$ $$2ab=k-4ac$$ $$b=\frac{k-4ac}{2a}$$

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