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For matrix $A= \left( \begin{array}{c} 1 & 1 \\ -1 & 1 \\ \end{array} \right) $ when I calculate the eigenvalues (without matlab) , I find $\lambda_1=1+1i$ and $\lambda_1=1-1i$ and when I use $eig$ syntax in matlab again the eigenvalues are $\lambda_1=1+1i$ and $\lambda_1=1-1i$ but when I use $svd$ syntax in matlab (singular value decomposition) I mean $A=U\Lambda V^H$ diagonal elements of matrix $\Lambda$ are not $1+1i$ and $1-1i$ now I'm confused and I don't know why diagonal elements of matrix $\Lambda$ are not $1+1i$ and $1-1i$

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Singular values are not eigenvalues, you can refer to the wiki.

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