Question about Notation What does $\mathbb{R}∗\mathbb{R}$ mean?
I'm sure this has been asked before, but I do not know how to search for notations in past questions.
 A: In group theory, $G ∗ H$ is defined as the free product of $G$ and $H$. It is an operation that constructs a new group which contains both $G$ and $H$ as subgroups, since it is generated by the elements of these groups. For definition, maybe the following link can be of help: http://mathworld.wolfram.com/FreeProduct.html.
A: Hatcher uses $X*Y$ to denote the join of two spaces, that is, the quotient of $X \times Y \times I$ by the identifications $(x, y_1, 0)$ with $ (x, y_2, 0)$ and $(x_1, y, 1)$ with $ (x_2, y, 1)$.  This is the space of all line segments joining points of $X$ with points of $Y$.  See page 9 of Hatcher's book on algebraic topology for more information.
If $X$ and $Y$ are closed intervals, the cube $X \times Y \times I$ gets collapsed to a tetrahedron.  In the case of $X=Y=\mathbb{R}$, I guess we get an "infinite tetrahedron".
A: This is not an answer to the question. Since it is not easy to search for mathematical notation, perhaps this can help to confirm where the OP saw the notation. I am making this CW - feel free other occurrences from math.SE which may be relevant.

Searching for "\mathbb Z \ast \mathbb Z" site:math.stackexchange.com
lead me to Georges Elencwajg's comment

Dear Akhil, I don't know about the existence of a purely algebraic proof. What I know is that  until a few years ago there was no purely algebraic computation of the algebraic fundamental group of the projective complex line minus three points (namely $\pi_1^{alg}(\mathbb P^1_{\mathbb C} \setminus \{0,1, \infty\})=\widehat{\mathbb Z\ast \mathbb Z}$).

Searching for "\mathbb Z * \mathbb Z \to \mathbb Z \times \mathbb Z" site:math.stackexchange.com
gives
this question:

The first is, Is $i_*: \pi_1(S^1 \vee S^1) \to \pi_1(S^1 \times S^1)$ injective?  My intuition is that no, this is not injective because $\pi_1(S^1 \vee S^1) = \mathbb{Z} * \mathbb{Z}$, the free group on two generators and $\pi_1 (S^1 \times S^1) = \mathbb{Z}\times \mathbb{Z}$.  However, I am not sure if this is in fact true and I am trying to figure out the best way to go about showing it.

And from an answer to the same question:

Consider a homomorphism $f: \mathbb{Z} \ast \mathbb{Z} \to \mathbb{Z} \times \mathbb{Z}$.
If $a$ and $b$ are the generators of $\mathbb{Z} \ast \mathbb{Z}$ then consider what $ab$ and $ba$ map to:
$f(ab) = f(a)f(b) = f(b) f(a) = f(ba)$

In both cases it seems to denote free product.
