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Decide which of the following statements are true, and which are false. Prove the true ones and provide counterexamples for the false ones.

a) If x_n is strictly decreasing and 0 <= x_n < 0.5, then x_n → 0 as n grows.

Answer False: since a function has to be strictly decreasing and bounded below to converge to a given number. The sequence could be decreasing, yet converging to another value.

take x_n = 1/6 + 1/n, the sequence is decreasing yet approaches 1/6, as n grows.

c) If x_n is a strictly increasing sequence and |x_n| < 1 + 1/n for n = 1,2,3,... , then x_n → 1 as n grows.

Can someone verify part a) and Can someone please help me with part c)?

Thank you.

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    $\begingroup$ Part a) looks good. For part c) what about $1/6-1/n=x_n$? $\endgroup$ – Jose27 Sep 17 '14 at 0:53
  • $\begingroup$ the sequence is strictly increasing, yet approaches 1/6 as n grows as n grows. Thus, it is false. However, I get confuse with the sequence being less than 1 + 1/n. $\endgroup$ – user3883 Sep 17 '14 at 1:03
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(c) False: Choose $x_n=\frac{1}{2}-\frac{1}{n}$ for $n = 1,2,3,... $

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    $\begingroup$ Then, wouldn't x_n approach 1 as n grows. $\endgroup$ – user3883 Sep 17 '14 at 1:13

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