1
$\begingroup$

There was this question on integration that I am correct with the answers section of my textbook upto a point. So I will only ask this last step of evaluation.

This is what the book says - enter image description here

And this is how my simplication ended up in -

enter image description here

As you can see both the book and my first part is same but I get a different final answer than book. The book has 1/2 inside the bracket where I have 1. I just dont know how the book got 1/2 or what I am missing out. Can anyone help me figure it out? :)

$\endgroup$

1 Answer 1

1
$\begingroup$

$$\left(\frac{1}{\sqrt{2}}\right)^{2n+1}=\left(\frac{1}{\sqrt{2}}\right)\left(\frac{1}{2}\right)^n\not=\left(\frac{1}{2}\right)\left(\frac{1}{2}\right)^n$$

$\endgroup$
1
  • $\begingroup$ Omggggggg How silly I was :o I went through this several times but couldnt catch my mistake :o Thank you alot $\endgroup$
    – M.S.E
    Sep 13, 2014 at 5:52

You must log in to answer this question.

Not the answer you're looking for? Browse other questions tagged .