Question: Find the equation of the parabola whose axis is parallel to the y-axis and which passes through the points (0,4) (1,9) and (-2,6)
Well as the parabola has its axis parallel to the y-axis and it is obviously opening upwards, the general form can be written as: $$(x-h)^2 = 4a(y-k)$$
Then I would have to go through the painstaking task of solving three variables from three equations. Obvious method to do it. I was wondering if there's any easier way of doing it?