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Today, I saw this equation on an assessment in class. Before I handed it in, I was sure to copy it down so I could ask for some help here.

Alright, I had a lot of work down, and I always messed up on one step near the end (which I don't remember, nor can I find out as I don't have the sheet with me). So if anyone can guide me through this problem, that would be great.

$4[x-(3-2x)]+5 = 3(x+11)$

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    $\begingroup$ So start writing. Show your steps, and we can point out where the trouble is. $\endgroup$ – MPW Sep 3 '14 at 2:50
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4(x-3+2x)+5 = 3x+33

12x-7 = 3x+33

9x = 40

x = 40/9

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    $\begingroup$ Looks like you just gave a man a fish... :( $\endgroup$ – MPW Sep 3 '14 at 2:51
  • $\begingroup$ The King takes no criticism! $\endgroup$ – King Squirrel Sep 3 '14 at 2:53
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    $\begingroup$ I actually laughed out loud. $\endgroup$ – layman Sep 3 '14 at 2:54
  • $\begingroup$ How did -2x become +2x in your first step? $\endgroup$ – Math878 Sep 3 '14 at 2:55
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    $\begingroup$ @KingSquirrel OHH. It seems like that's where I messed up originally. $\endgroup$ – Math878 Sep 3 '14 at 3:02

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