Two vectors are perpendicular when their dot product is zero. But how to get the dot product of two lines?

$r_1= (8,-3,1)+s(12,-5,0)$

$r_2= (1,14,3)+t(5,a,b)$

The question asks for the value of $a$ given that the two lines are perpendicular.

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    $\begingroup$ The 2 lines are perpendicular if $(12,-5,0).(5,a,b)=0$ which gives $a=12$. $\endgroup$ – Paracosmiste Aug 23 '14 at 14:44

The vectors $(12,-5,0)$ and $(5,a,b)$ are the direction vectors of the lines. If the dot product of those two vectors is zero, then the lines are perpendicular.

Hence you have to calculate: $$(12,-5,0)\cdot(5,a,b)=0$$

This gives: $12\cdot5-5\cdot a=0 \Longleftrightarrow 60-5a=0 \Longrightarrow \boxed{a=12}$


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