# Complex Analysis Rouches Theorem

I am struggling to understand the solution below. I understand how to apply Rouches theorem when showing that there are a certain number of zeroes in a circle / annulus.

In this example (where they ask to show that there is a zero in each quadrant, I am not so sure. I dont really understand why they use inequalities with the real and imaginary parts.

I also dont understand why you can say that since since each of the roots of $z^4+1$ lie in a separate quadrant, then they must lie in separate quadrants of $z^4+z+1$ also. Rouché's theorem says that if $f$ and $g$ are analytic inside and on a closed contour $\Gamma$ and $|g| < |f|$ on $\Gamma$, then $f$ and $f+g$ have the same number of zeros inside $\Gamma$.
The inequalities are showing that $|g| < |f|$ on the pieces of axes and circle that make up the boundary of each pie-slice. Once you have that, and you know that $f$ has one root inside each pie-slice, Rouché tells you that $f+g$ has the same property.
• @ArchieJudd Note that $|f(z)|$ and $|g(z)|$ are invariant under reflection in the coordinate axes. So if it works for one slice, it works for the other three as well. – Robert Israel Aug 18 '14 at 18:05