# Why is sequence $(1+\frac{1}{n})^{n+1}$ descending? [duplicate]

I was studying the proof of $e$ number when I noticed something:

Why is the sequence $(1+\frac{1}{n})^{n+1}$ descending? It starts ascending with grater n but in one moment it starts descending? Why is that? On what $n$ this happens?

Edit: Let me try to rephrase the question... How come that sequence $(1+\frac{1}{n})^n$ rises, but the sequence $(1+\frac{1}{n})^{n+1}$ falls, just because of the one more 1+1/n multiplication (power)?

• See this. – David Mitra Aug 12 '14 at 9:36
• I edited the question with more details – slimDeviant Aug 12 '14 at 9:41