Trigonometric functions and inverse functions Can we write $\sin x > a$ as $x > \arcsin a$. Please explain the process. Is it possible for all ratios with any inequality sign.
 A: Since $\sin x$ is as well as $\arcsin x$ increasing, we can write that* $x>\arcsin a$ if $\sin x>a$.
*Note that this is not always true, consider the sequence of equations:
$$\sin x>a\\\arcsin(\sin x)>\arcsin(a)\\x>\arcsin a\text{ if }x\in[-\pi/2,\pi/2]\wedge a\in[-1,1]$$
because a must satisfy $\arcsin$'s domain demand and $\arcsin\sin x$ is not always $x$.
This is the graph of $\arcsin\sin x$ which is exactly equal to x in $[-\pi/2,\pi/2]$.

So you'll end up for $x\in[\pi/2,3\pi/2]$
$$\arcsin(\sin x)>\arcsin(a)\\
\pi-x>\arcsin(a)$$
Not the thing you mentioned.Other similiar functions are $\tan$ and $\sec$.
Also, if we worked with cos, you'll end up something like this:
$$\cos x>a\\\arccos(\cos x)<\arccos(a)\\x<\arccos a\text{ if }x\in[-\pi/2,\pi/2]\wedge a\in[-1,1]$$
The reason I have inverted the inequality is that $cos x$ is increasing whereas $\arccos x$ is decreasing.Other similiar cases are $\cot$ and $\csc x$.
A: Strictly Decreasing Function
If $f(\beta)<f(\alpha)$ for all $\beta > \alpha$, then $f(x)$ is a strictly decreasing function.
All you have to do is determine if the function in question is strictly decreasing or not. If it's strictly decreasing then the direction of the inequality changes. Otherwise, the direction remains the same.
Examples
\[ f(x)=\arcsin(x) \]
$f(x)$ is not a strictly decreasing function, the direction of the inequality stays the same.
\[ f(x)=\arccos(x) \]
$f(x)$ is a strictly decreasing function, so the direction of the inequality changes.
\[ f(x)=-x \]
$f(x)$ is a strictly decreasing function. This is why the direction of an inequality changes when you multiply or divide an inequality by a negative number.
A: Only for values of x in the first and fourth quadrants -- which is to say the fundamental domain of arcsin.  Something similar works for all trigonometric functions in the first quadrant; sin tan and sec keep the inequality direction the same; cos cot and csc switch it.
