I don't know why but I just can't simplify this expression and its driving me mad!! Could someone please help me with the steps?

$\frac {2^n 9^{2n+1}}{6^{n-2}}$

I know the answer is 4 x $3^{3n + 4}$ I just can't get there.

Thanks in advance :)


Notice that:




Then use exponent rules.

  • $\begingroup$ Thank you!!! Can do it now. Couldn't see that step by myself. Much appreciated. $\endgroup$ – Dani Aug 4 '14 at 5:00
  • $\begingroup$ You're welcome!!! Glad you are able to solve the problem now. $\endgroup$ – user71352 Aug 4 '14 at 5:00
  • $\begingroup$ Oh no I still can't get it!!! I've done: $\frac {2^{n} 3^{4n+2}}{2^{n} 3^{4n} 3^{n} 3^{-2}}$ $ \frac {2^{n} 3^{4n} 3^{2} 2^{2} 3^{2}}{2^{n} 3^{n}}$ $ \frac {2^{n}3^{4n}18^{2}}{6^{n}}$ $ \frac {3^{4n} 18^{2}}{3}$ I can see this isn't going to lead anywhere useful! Can you please help set me in the right direction a bit more? Thank you $\endgroup$ – Dani Aug 4 '14 at 5:12
  • $\begingroup$ Can you show me what you are getting? $\endgroup$ – user71352 Aug 4 '14 at 5:15
  • $\begingroup$ Ok the denominator on that first one should say $2^{n} 2^{-2} 3^{n} 3^{-2}$ $\endgroup$ – Dani Aug 4 '14 at 5:19

$$\frac {2^n 9^{2n+1}}{6^{n-2}}$$ $$\frac {2^n 3^{4n+2}}{2^{n-2}3^{n-2}}$$ $$2^{(n)-(n-2)}3^{(4n+2)-(n-2)}=4*3^{3n+4}$$


Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.