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Possible Duplicate:
Infinity = -1 paradox

$1+2+4+8+16+\ldots = \infty$

$LHS=1(1+2+4+8+16+\dots)$

$LHS=(2-1)(1+2+4+8+16+\ldots)$

$LHS=(2+4+8+16+32+\ldots)-(1+2+4+8+16+\ldots)$

$LHS=2+4+8+16+32+\ldots-1-2-4-8-16-\ldots$

$LHS=-1$

$\therefore \space -1 = \infty$

what

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    $\begingroup$ Hi, and welcome to Math.SE! Your question has actually been asked before, in a slightly different form; see the linked question above. That doesn't mean there's anything wrong with your question, just that we don't want to have duplicates. $\endgroup$ – Zev Chonoles Dec 4 '11 at 10:59

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