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I am reading a mathematics book for poker and came across this equation:

$P$ = pot bets
$c$ = frequency player x calls
bluff bet = 1

(pot size)(frequency x folds) = (bluff bet)(frequency x calls)
$P(1-c) = c$
???
$c = P/(P+1)$

I need help to understand the steps between.

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1 Answer 1

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$P(1-c)=c$

$P -Pc=c$

$P = c+Pc$

$P= c(P+1)$

$c = P/(P+1)$

Is this what you mean?

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  • $\begingroup$ Yes, thank you! But I still have a problem understanding $c + Pc$ to $c(P+1)$. I'm so new to this. :D $\endgroup$
    – JimmyRare
    Jul 13, 2014 at 12:28
  • $\begingroup$ It's factorization. Try multiplying out c(P+1) and see that you get the same. $\endgroup$
    – user119615
    Jul 13, 2014 at 12:31
  • $\begingroup$ Indeed. I guess I'll head back to algebra fundamentals. $\endgroup$
    – JimmyRare
    Jul 13, 2014 at 12:32

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