Submodules of semi-simple modules Let $R$ be a ring (with unity, not necessarily commutative) and let $P$ be an irreducible $R$-module. Let 
$$M=\bigoplus_{i=1}^r P$$
be a direct sum of $r$ copies of $P$, for some $r\geq 1$. Then, $M$ is semi-simple by "definition". Now, let $N$ be a submodule of $M$. Is $N$ necessarily isomorphic to a direct sum of copies of $P$? If so, can you prove it? If not, could you provide an example? 
My intuition tells me that the answer is yes... If $N$ is a submodule of $M$, then $N$ itself is semi-simple, so it is a direct sum of irreducible submodules of $N$, which are also submodules of $M$... This reduces the question so that we can assume $N$ to be irreducible, and then the question is whether $N\cong P$? I am not sure how to prove that. Perhaps there is some exotic $M$ such that there is another decomposition 
$$M=Q\oplus \bigoplus_{i=1}^{r-1} L_i$$
with $Q$ and $L_i$ irreducible but $Q\not\cong P$? In other words, if $M$ is direct sum of irreducibles... is said decomposition unique? Do we need to assume Artinian and Noetherian here, to use the Jordan-Holder theorem, or can this be proved without those assumptions?
 A: First of all, let's see why it's true for the finitely generated case.
If there were a simple submodule $Q\ncong P$ in $M\cong \bigoplus_{i=1}^r P$, then you could find a composition series using $Q$ as a link in the chain. Of course $\{0\}\subseteq P \subseteq P\oplus P\subseteq P\oplus P\oplus P\subseteq\ldots \subseteq M$ is another composition series. But obviously all of the composition factors of $M$ are isomorphic to $P$, whereas the other composition series has a factor isomorphic to $Q$. The Jordan-Holder theorem tells us this is not possible.
Now what if $M\cong \bigoplus_{i\in I}P$ for some potentially infinite set $I$? Suppose again such a $Q\ncong P$ exists. It's cyclic, so it must be contained in a submodule $N=\bigoplus_{i\in F} P$ for a finite subset $F\subseteq I$. But our previous proof shows $N$ can't contain such a $Q$. So no such $Q$ exists, and all simple submodules are isomorphic to $P$.
So yes, the result you're seeking for "homogeneously semisimple modules" is true.
