Wedge product and linear subspace I am trying to understand the relationship between the wedge product and linear subspace. Let $e_1,\cdots, e_4$ be the standard basis of $\mathbb{R}^4$.  The wedge product $$(e_1+2e_2)\wedge (3e_1+e_3+e_4) $$ can be thought of as the oriented linear subspace generated by the vectors $e_1+2e_2$ and $3e_1+e_3+e_4$. 
Upon expanding we get
$$e_{13}+e_{14}-6e_{12}+2e_{23}+2e_{24},$$ where $e_{ij}=e_i\wedge e_j$. Each $e_{ij}$ can be thought of as the linear subspace spanned by $e_i,e_j$. But what role do the coefficients $1,1,-6,2,2$ play?
 A: These coefficients are called Plucker coordinates. There are many ways of thinking about them; the following is perhaps the most geometric.
Take your linear space (the span of $e_1+2e_2$ and $3e_1+e_3+e_4$) and project it onto $\mathrm{Span}(e_1, e_2)$. Then this linear map reduces area by a factor of 
$$\frac{6}{\sqrt{1^2+1^2+6^2+2^2+2^2+0^2}}.$$
If you project onto $\mathrm{Span}(e_1, e_3)$ instead, then the numerator changes to $1$ (the coefficient of $e_1 \wedge e_3$) and the denominator stays the same. The sign of the Plucker coordinate tells you whether the projection is orientation preserving or reversing.
Note: I am using the inner product on $\mathbb{R}^4$ to measure areas. Without this, I could still make sense of a ratio of two Plucker coordiantes, but there wouldn't be a good way to interpret one Plucker coordinate by itself.
A: As you mention in the comments, there is a 1-1 correspondence between subspaces and unit simple $m$-vectors in $\wedge^m\mathbb R^n$. When you expand out $v_1\wedge v_2$ in a basis, the result is no longer a simple $2$-vector but a linear combination of simple $2$-vectors, so you should not try to interpret the coefficients of this expansion as having geometric meaning.
