I need a relation which is not reflexive, not symmetric, and not transitive I need an example of a relation which is simultaneously not reflexive, not symmetric, and not transitive.  Any accessible examples?  Thanks in advance.
 A: A simple one is : Define $R$ on $\mathbb{Z}$ by $(x,y)\in R$ if and only if $x-y=10$.
A: On $\mathbb{N}$, consider
 $$a \sim b \iff a +2b = 5,$$
then


*

*$1\nsim 1$,

*$3\sim 1$ but $1 \nsim 3$,

*$3\sim 1, 1 \sim 2$ but $3 \nsim 2$.
A: How about:  "is the square of", defined on the set of positive integers?  In other words,
$$a \sim b \iff a=b^2$$
This relation is not reflexive (most numbers are not their own square), not symmetric (if $a$ is the square of $b$ then in most cases $b$ is not the square of $a$) and not transitive (if $a$ is the square of $b$ and $b$ is the square of $c$ then in general $a$ will not be the square of $c$).
A: Minimal example:
$X = \{0,1,2\}$
$R = \{(0,1),(1,2)\}$
A: Here's a non-mathematical one: "is the father of".
You are not your own father. You are not your father's father. Your father's father is not your father.
A: Less than, but close:
 $$a \sim b \iff a < b  \ \ \text{ but } \ \ a > (b-1)$$
So


*

*$1\nsim 1$,

*$0.5\sim 1$ but $1 \nsim 0.5$,

*$0\sim 0.5$, $0.5 \sim 1$, but $0 \nsim 1$.
A: Why not $a\sim b$ if and only if either $a=3$ and $b=4$ or $a=4$ and $b=5$?
A: Take any directed acyclic graph amd the arcs form an irreflexive, asymmetric antitransitive relation of its nodes. Then add some loops (not to all nodes), back-arcs (not to all of them) and some skip-forward arcs (not to all directed paths) and you have a more general relation with your restrictions.
Ex: 
1) Strong version: a->b, b->c, c->d, a->e
2) Then add: a->a, b->a,a->d
A: Think of three points $u, v, w$ with relation $R = \{(u, v), (v, w) \}$. So $u$ is related to $v$ and $v$ is related to $w$. This is not reflexive since $(u,u) \notin R$, not symmetric because $(v, u) \notin R$ and not transitive because $(u, w) \notin R$.
A: What beats what in Roshambo or "Rock, Paper, Scissors" is such a relation.


*

*not reflexive: rock does not beat rock.

*not symmetric: rock beats scissors, but scissors does not beat rock.

*not transitive: rock beats scissors and scissors beats paper, but rock does not beat paper.
The same is true of "Rock, Paper, Scissors, Lizard, Spock".
