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I have to matrices:

$$A=\pmatrix{1&a&1\\1&0&a\\1&2&0} ; \quad B= \pmatrix{1&b&3\\2&1&0}$$

The task is to determine $AB, AB^T, BA$

I think i cannot calculate the matrix of $AB$ because $\text{Columns} \ A = 3$ is not $\text{Rows} \ B = 2$

But i can calculate $BA$:

$$BA=\pmatrix{4+b&6+a&1+ba\\3&2a&2+a}$$

Now my question is, what is meant with $ AB^T$ ? Thanks

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    $\begingroup$ Do you know what $B^T$ is? $\endgroup$ – Git Gud Jun 29 '14 at 10:47
  • $\begingroup$ @GitGud no i dont know $\endgroup$ – John Smith Jun 29 '14 at 10:48
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    $\begingroup$ The superscript $T$ denotes the matrix transpose. Basically it's a new matrix whose $i^{\text{th}}$ column is the $i^{\text{th}}$ line of the original matrix. $\endgroup$ – Git Gud Jun 29 '14 at 10:50
  • $\begingroup$ John, you may use \text{anything} for writing text in LaTeX. [TeX TIP] $\endgroup$ – Kushashwa Ravi Shrimali Jun 29 '14 at 10:52
  • $\begingroup$ Perhaps you should understand what transpose of a matrix is first! $\endgroup$ – pushpen.paul Jun 29 '14 at 14:32
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$A\times B^T$ means the matrix $A$ multiplied by the transpose of $B$. Given some matrix $A$, the transpose, $A^T$, is a matrix such that the columns of $A$ are the rows of $A^T$ and the rows of $A$ are the columns of $A^T$. Thus we see that $$B^T= \left(\begin{matrix} 1 & 2 \\ b & 1 \\ 3 & 0 \\ \end{matrix}\right) .$$ You can now evaluate $A\times B^T.$

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Hint: $B^{T}$ means transpose of $B$. You can read about transpose here.

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