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Assume that $u:[0,1]\to \mathbb{R}$ is a absolutely continuous (A.C. for short), non decreasing function. Suppose that $u(0)=\alpha$ and $u(1)=\beta$. Take any open interval $J\subset [\alpha,\beta]$. Is it possible to find a open interval $I\subset [0,1]$ such that $$u(I)=J.$$

The Cantor function shows that A.C is needed, however, I fail to see if it is sufficiently. Any idea is appreciated.

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  • $\begingroup$ What do you mean by "non decreasing"? $\endgroup$ – Stefan Mesken Jun 20 '14 at 15:29
  • $\begingroup$ @user155124, $u(x)\le u(y)$ if $x\le y$. $\endgroup$ – Tomás Jun 20 '14 at 15:30
  • $\begingroup$ Ok, so you actually mean "increasing". Then my counterexample doesn't work. $\endgroup$ – Stefan Mesken Jun 20 '14 at 15:32
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Since $u$ is continuous and $J$ is open, it follows that $u^{-1}(J)$ is open.

Since $u$ is monotone and $J$ is an interval, it follows that $u^{-1}(J)$ is an interval.

Therefore, $u^{-1}(J)$ is an open interval. Since $J$ lies in the range of $u$, we have $u(u^{-1}(J))=J$.

Nothing to do with absolute continuity.

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