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Find the quantile function of $$q=F(x)=[(1-\exp(-bx))^c]*[1+d-d*(1-\exp(-bx))^c]$$ , where $b, c$ are positive real and $-1<d<1$. Its answer is gif

Any help/hint is most welcome.

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1 Answer 1

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Take the term in the first square bracket, call it $z$, then you have a quadratic in $z$. Solve for $z$ then it is easy to solve for $x$. The 2d is in the wrong place in your solution, just a type I guess. Not sure why just one root of the quadratic is used. Also think about what happens when d<0.

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  • $\begingroup$ thanks your help is much appreciated,and -1<d<1. $\endgroup$
    – SA-255525
    Jun 15, 2014 at 7:40
  • $\begingroup$ when d<0 the denominator will mean you are taking the c-th root of a -ve quantity. $\endgroup$
    – user121049
    Jun 15, 2014 at 8:29
  • $\begingroup$ when i said -1<d<1 , i really meant abs(d)<=1. It was my mistake. $\endgroup$
    – SA-255525
    Jun 15, 2014 at 9:41

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