# Is it possible to obtain a sphere from a quotient of a torus?

I understand that a torus is obtained from a sphere by adding a handle. I'm working on a question which is asking if it is possible to obtain a sphere from a quotient of a torus? It seems like this should be possible by perhaps identifying the insides of the torus? But I'm not quite sure how to properly express this.

Help is very much appreciated.

• Does quotient just mean surjective continuous map? Do you know the description of the torus as a square with opposite sides identified? If you identified those opposite sides to a point, I think you'll get a sphere. – CJD Jun 10 '14 at 13:17
• That is what I was thinking, but do you actually get a sphere or just a point? – Wooster Jun 10 '14 at 13:18
• See this question: math.stackexchange.com/q/809595/4583 – Ayman Hourieh Jun 10 '14 at 13:21
• Wooster, you get a sphere, because the interior of the rectangle hasn't changed. This is topologically the same as taking a closed disk and identifying its boundary to a point, which likewise gives you a sphere. – Ted Shifrin Jun 10 '14 at 13:36
• Every positive-dimensional compact manifold is homeomorphic to a quotient of any other compact positive-dimensional manifold. – user98602 Aug 3 '15 at 18:39

Consider the torus sitting in $\mathbb R^3$ like a donut on a table. Then you see that it is invarant by a rotation of $180$ degrees around an horizontal axis. The quotient by such involution is a sphere and the projection is wat is usually called a branched cover (with four branch points).