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I have the following:

$6.4 = -\log\dfrac{5-v*0.1}{50+v}$

I would like to know how to solve the equation in order to get $v$'s value. Thank you very much.

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  • $\begingroup$ What did you try? $\endgroup$ – Priyatham Jun 8 '14 at 11:27
  • $\begingroup$ $a=\log b\iff 10^a=b$. (I assume $\log$ is base $10$.) $\endgroup$ – David Mitra Jun 8 '14 at 11:35
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Take anti-logarithms of $-6.4 = \log\dfrac{5-v*0.1}{50+v}$ and then it is easy.

For example if your logarithms are base $e$ then $e^{-6.4} = \dfrac{5-v*0.1}{50+v}$

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