# How to clear variable $v$ from logarithmic equation

I have the following:

$6.4 = -\log\dfrac{5-v*0.1}{50+v}$

I would like to know how to solve the equation in order to get $v$'s value. Thank you very much.

• What did you try? – Priyatham Jun 8 '14 at 11:27
• $a=\log b\iff 10^a=b$. (I assume $\log$ is base $10$.) – David Mitra Jun 8 '14 at 11:35

Take anti-logarithms of $-6.4 = \log\dfrac{5-v*0.1}{50+v}$ and then it is easy.
For example if your logarithms are base $e$ then $e^{-6.4} = \dfrac{5-v*0.1}{50+v}$