1
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Using each of the digits 1,2,3,4,5,6,7,8 exactly once fill in the boxes so that no consecutive number is adjacent or cross to that number.

Example 1:

          -----
         |  1  |
 ----------------------
|   2(x) |     | 3(v)  |
 ----------------------
|        |     |       |
 ----------------------
         |     |
          -----

In the above example 1, 2 is invalid as 1 is cross to 2 also 1 & 3 are valid as the are not consecutive.

Example 2:

         -----
        |     |
 --------------------
|       |     |      |
 --------------------
|       | 6(x)|      |
 --------------------
        |  5  |
         -----

In the above example 2, 5 & 6 are invalid,instead of 6 ,the valid ones are 1,2,3,7,8.

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  • 2
    $\begingroup$ I have some trouble seeing the pictures. It looks as if there are $8$ little squares, not $9$. $\endgroup$ – André Nicolas Jun 5 '14 at 6:07
  • $\begingroup$ By "cross to" do you mean diagonal to? $\endgroup$ – Lost Jun 5 '14 at 6:09
  • $\begingroup$ yes i meant diagonal.Shown in example 1 $\endgroup$ – lsunny Jun 5 '14 at 6:11
  • $\begingroup$ Do you know the answer, or are you looking for an answer (and way to solve it)? $\endgroup$ – Steven Stadnicki Jun 5 '14 at 6:16
2
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A number placed in one of the two center squares is adjacent to all but one of the other squares. That means the number can be consecutive with at most one other allowed number, which must go in the far square. This forces us to put 1 and 8 in the center squares:

 ?
?1?
?8?
 ?

and 2 and 7 must go in the top and bottom:

 7
?1?
?8?
 2

From here, a bit of trying stuff out gets us one of the 8 possible solutions:

 7
413
685
 2

The other solutions are

 7
315
684
 2

and the 6 solutions obtained by mirroring the above solutions across the puzzle's horizontal and vertical lines of symmetry.

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