Given that $\log12=1.0792$ and $\log4=0.6021$, solve $\log8$ without a calculator.
I am familiar with the following three rules:
- Product rule: $\log(a\cdot b)=\log a+\log b$
- Quotient rule: $\log(a/b)=\log a-\log b$
- Power rule: $\log(a^b)=b\cdot\log a$
But I honestly don't see how they help in this case. Any way you slice it, it seems like it's necessary to introduce $\log2$, which is not given. Am I missing something?