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How would go about cancelling out the $\log_2$. Is it possible for the TI 89 to handle this? I'm not sure how to put $\log_2$ in my TI 89.

$20=30\cdot \log_2(1+x)$

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  • $\begingroup$ @Bananarama If you're going to make a trivial edit to improve formatting, at least do it all the way. $\endgroup$
    – Emily
    Jun 3, 2014 at 19:52

2 Answers 2

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$$\log_b a = \frac{\log_{X} a}{\log_{X} b},$$

where $X$ is whatever you want it to be, usually either $e$ (e.g. $\ln$) or $10$. It doesn't matter! Literally any $X$ will work, so whatever your calculator uses as its default base, just use that and do log(a)/log(b).

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$\log_2(x+1)=\frac{20}{30}=\frac{2}{3}\implies x+1=2^{\frac{2}{3}}=(\sqrt[3]{2})^2\implies x=(\sqrt[3]{2})^2-1$

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