There are six boys and five girls in a school tennis club. A team of two boys and two girls will be selected to represent the school in a tennis competition.
(a) In how many different ways can the team be selected?
(b) Tim is the youngest boy in the club and Anna is the youngest girl. In how many different ways can the team be selected if it must include both of them?
(c) What is the probability that the team includes both Tim and Anna?
Those are the questions. The markscheme says:
I need some clarification:
For (a), you need to divide by two because the order doesn't matter?
(b), it's $(6-1)\times(5-1)$ because you are excluding one person from the boys and one person from the girls; only 5 of the 6 are eligible for the boys, and 4 of the 5 are eligible for the girls?
(c), divide the number of ways Tim and Anna can be chosen by the total.
Is my thinking correct? Is there a better way to phrase my thinking?