I have invented two sets of positive integers: highly regular numbers and superior highly regular numbers.
A positive integer $m \leq n$ is a regular of the positive integer $n$ if all prime numbers that divide $m$ also divide $n$.
So for example:
- 4 has 3 regulars: 1, 2, 4.
- 6 has 5 regulars: 1, 2, 3, 4, 6.
- 8 has 4 regulars: 1, 2, 4, 8.
- 9 has 3 regulars: 1, 3, 9.
- 10 has 6 regulars: 1, 2, 4, 5, 8, 10.
- 12 has 8 regulars: 1, 2, 3, 4, 6, 8, 9, 12.
- A prime number has 2 regulars: 1 and itself.
$r(n)$ denotes the function which counts the quantity of regulars of the positive integer $n$.
A highly regular number is a positive integer $n$ for which $r(n) > r(q)$ for all positive integer $q < n$.
So a highly regular number is a positive integer with more regulars than any smaller positive integer.
I’ve found that the first highly regular numbers up to 210 are: 2, 4, 6, 10, 12, 18, 24, 30, 42, 60, 84, 90, 120, 150, 180, 210.
A superior highly regular number is a positive integer $n$ for which there is an $\epsilon > 0$ such that: $$\frac{r(n)}{n^\epsilon} \geq \frac{r(k)}{k^\epsilon}$$ for all positive integers $k > 1$.
I've found that the first superior highly regular numbers up to 210 are: 2, 6, 30, 210.
Consequently, I’ve made a conjecture: Every primorial is a superior highly regular number, and every superior highly regular number is a primorial.
Could someone prove that my conjecture is true?