What does "identity map $id$" mean? What does "identity map $id$" mean in this context?
Two metrics $d_1$ and $d_2$ on $X$ are said to be Lipschitz equivalent if the identity map $id\colon (X,d_1)\to (X,d_2)$ is bilipschitz.
 A: The identity map always means $Id(x)=x$, in every context.
In this one, note that the underlying set $X$ is the same, so there is sense to speak about the identity map. However the metrics may be different, which would imply a different topology.
The identity map need not be continuous when going from one topology to another (e.g. $x_0$ is an isolated point in the range, but not in the domain), but in a sense it measures some compatibility between the topologies and in this case the metrics.
A: The symbol 'id' is often used to refer to the identity map, which is the map which takes every element of a set $X$ to itself:
$$\begin{align}
\textrm{id} : & X \to X \\
& x \mapsto x
\end{align}$$
or, phrased differently, id is the map from $X$ to $X$ that satisfies $\textrm{id}(x)=x$ for every $x\in X$.
A: It is the map $X\to X$ given by the formula $x\mapsto x$.
It is the identity map of the underlying set $X$ of the two metric spaces you consider. There is not really an identity map from $(X,d_1)$ to $(X,d_2)$ because these are not the same metric spaces.
