Can someone share what usual strategies they pursue for proving Lipschitz? I usually use two strategies but they are very restrictive on the type of functions they require. One is by checking the bound of the continuous derivative, the other is by use of the mean value theorem. Unfortunately the mean value theorem cannot be used in Rn.

Also, the function I'm working is of the type: $\int_0^t f(x(s),y(s))ds$

I am looking for Lipschitz in both $(x(s),y(s))$ with the integrand being bounded by a function of $s$. Lipschitz here does not need to be a constant but may be a function of $t$.

Thanks in advance

  • 1
    $\begingroup$ In general, just use the definition. (Not intended to be sarcastic.) As an analogy, showing Lipschitz by using the fact that the derivative is bounded is like using short cut rules for differentiating functions (power rule, product rule, etc.). The short cut rules work when you're in relatively nice situations, but for something like $f(x) = x^{2}\sin(1/x)$ with $f(0)=0,$ you have to use the definition of the derivative (as a limit). In general, there's going to be some inequality "dirty work" involved in showing something is (or is not) Lipschitz when differentiability isn't available. $\endgroup$ – Dave L. Renfro May 15 '14 at 14:55
  • $\begingroup$ @DaveL.Renfro tks. I always start with the definition of course, but when the function is not differentiable I usually run into problems when it is a more complicated function. $\endgroup$ – The Mighty Algernon May 15 '14 at 18:18

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Browse other questions tagged or ask your own question.