Well the question speaks for itself really.

I worked the problem down to

$|iw|=3|1-w|$, where i is the imaginary number,

but I don't understand how to get to the next step, which the mark scheme tells me is


Why can you just flip it round?


$$|ab|=|a||b|$$ where $a,b$ are complex

Here $a=i,b=w$

Again, $$a=-1\implies|-b|=|b|\implies |w-1|=|1-w|$$


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