I am trying to find the area of the parallelogram with vertices (4,1), (6, 6), (7, 7), and (9, 12).
So I believe the way to solve this problem is through the cross product and then taking the magnitude. However, I got the wrong answer and I am now rethinking my methods.
My original work:
Point A:(4,1) Point B: (6,6) Point C:(7,7) Point D: (9,12)
I took the cross product of AB and AC and took the magnitude of that and ended up getting sqrt(369).
I would appreciate the help. I am kind of stumped.