I'm curious about the invariant factors of $(\mathbb{Z}/(1000))^\times$. I put down $$ (\mathbb{Z}/(1000))^\times\cong(\mathbb{Z}/(8))^\times\oplus(\mathbb{Z}/(125))^\times $$
It's easy to compute by hand that $(\mathbb{Z}/(8))^\times\cong\mathbb{Z}/(2)\oplus\mathbb{Z}/(2)$ and by a theorem of Gauss, $\mathbb{Z}/(125))^\times\cong\mathbb{Z}/(100)$ as it is cyclic.
Does this mean the list of invariant factors is just $(2,2,100)$?