# What is the sample path of a stochastic process

Assume $\Omega$={head, tail}, let T=$\mathbb N$ and $X_t$ $t\in T$ be a collection of i.i.d random variables following Bernoulli distribution. Since a stochastic process is a function of two variables. When $\omega$ is fixed, we get a sample path, so when fix $\omega$={head}, Is the sample path of $X_t(\omega)$ be the constant 1? But a realization of coin tossing can't be always head . So where is my fault?

The error is that $\Omega=$ {heads,tails}$^T$, where {heads,tails}$^T$ is the set of all functions from $T$ to {heads,tails}. So a typical $\omega$ is an infinite sequences whose entries are either heads or tails.
• So the space of brownian motion is $\mathbb C(R^+,R)$, I see. May 10, 2014 at 8:47
• What does $\Omega=\{heads,tails\}^T$ mean? Thanks! Aug 29, 2016 at 19:09
• @SergioParreiras How to define a measure on a $\Omega=\{heads, tails\}^T$ if $\omega\in \Omega$ is a function? Sep 5, 2016 at 14:11