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This is to show that the minimal polynomial does not determine the jordan normal form. I've tried a few but haven't got anywhere.

Why is this marked as duplicate? The other post does not give me an answer.

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marked as duplicate by M Turgeon, Dietrich Burde, naslundx, user61527, user1551 May 8 '14 at 19:46

This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.

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What about the minimal polynomial $(X - 1)(X - 2)$?

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