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simplify:

(1) $f= pq+r$

(2) $g=a+bc+a'bc'd$

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closed as off-topic by user99914, Somos, Lord Shark the Unknown, Jyrki Lahtonen, Xander Henderson Jul 27 '18 at 13:00

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$$pq + r = (p+r)(q+r)$$

That's not necessarily a simplification. Simplification depends on the required or desired form. The left hand side is in disjunctive normal form, and the right-hand side is in conjunctive normal form.

$$\begin{align} a + bc + a'bc'd & = a + bc + bc'd \\ \\ & = a + b(c + c'd)\\ \\ & = a + b(c + d) \\ \\ & = a + bc+bd\end{align}$$

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