1
$\begingroup$

enter image description here

Hi! I am currently working on some calc2 online homework problems and I am having difficulty with this problem. I was trying to use the polar coordinates (d,a)with the equation of the line thus being r=dsec(theta-a). I tried solving for d by setting d equal to sqrt((-19)^2+(-6)^2) which then came out to be 137621/6907. I then tried solving for a by setting it equal to arctan(-6/-19) which came out to be 17.52556837. I then plugged everything into the equation of the line which i had as r=dsec(theta-a) to get r= (137621/6907)sec(theta-17.52556837). Clearly my answer is wrong but I do not know why. If someone can help me solve this problem I would greatly appreciate it.

$\endgroup$
  • 2
    $\begingroup$ Ahh... my eyes are burning! $\endgroup$ – Sandeep Silwal Apr 27 '14 at 20:42
1
$\begingroup$

The line is

$$L:\;\; y=-\frac{19}6x-\frac{208}3$$

and passing to polar coordinates:

$$r\sin\theta=-\frac{19}6r\cos\theta-\frac{208}3\implies r=-\frac{416}{6\sin\theta+19\cos\theta}$$

$\endgroup$
  • $\begingroup$ webworks is not accepting this as the correct answer $\endgroup$ – user124539 Apr 27 '14 at 21:17
  • $\begingroup$ My condolences for that webwork...whatever that is. You check my answer and try to follow it. Either I did some mistake or I didn't. If I did fix it, or at least find it, otherwise I did no mistake and that web..whatever is wrong. $\endgroup$ – DonAntonio Apr 27 '14 at 21:18

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.