There are two touching circles inscribed in a $60^\circ$ angle. The distance between the vertex of the angle and the center of the smaller circle is $5j$. What is the ratio of the surfaces of the two circles?
The radius of the large circle is three times that of the small circle. This is easy to see if you draw things on a triangular grid:
Since area scales with the square of the radius, you get an area ratio of $9$. The scale of things, in particular that distance $AD$, is irrelevant for this computation.