# Matrix exponential proof

I am solving a problem: $$A^3=\alpha^2A\implies \exp(A)=E+\frac{\mathrm{sinh}\alpha}{\alpha}A+\frac{\mathrm{cosh}\alpha-1}{\alpha^2}A^2;\, \alpha\in\mathbb{C},\,A\in\mathbb{M}_{n\times n}(\mathbb{C})$$ and I am stuck. I did prove the statement, but the proof turned out to be faulty and now I have to begin from a scratch(well, not from a scratch, the eigenvalues of the matrix are rather obvious) and I'd need a little guidance.

• What's the matrix E? – JPi Apr 14 '14 at 10:55

Hint. In this case I wouldn't use the "smart" method of calculating the exponential, but go back to the definition via Taylor series. If $A^3=\alpha^2A$ then $A^4=\alpha^2A^2$ and $A^5=\alpha^2A^3=\alpha^4A$ and so on; therefore \eqalign{\exp(A)&=I+A+\frac{1}{2!}A^2+\frac{1}{3!}A^3+\frac{1}{4!}A^4+\cdots\cr &=I+A+\frac{1}{2!}A^2+\frac{1}{3!}\alpha^2A+\frac{1}{4!}\alpha^2A^2+\cdots\cr &=I+(\cdots)A+(\cdots)A^2\ .\cr} I'm sure you can now fill in the gaps. Good luck!