# Finding angle in isosceles triangle

An isosceles triangle $ABC$ has $AB=AC$. Angle $A$ measures $20^\circ$. On $AC$, point $E$ is such that $AE=BC$. The task is to find the measure of angle $BEC$ without using trigonometry. How can one go about this?

• Point E is on AC. EAC will be 0. – Satvik Mashkaria Apr 13 '14 at 17:45
• I can't see how knowing $\;BC=AE\;$ can be helpful without trigonometry in this case... – DonAntonio Apr 13 '14 at 17:47
• Investigate Euclid's Elements Book 1 Proposition 5 for an idea of how to proceed. – JEM Apr 13 '14 at 17:49
• Its simple angle chasing... – Sawarnik Apr 13 '14 at 17:54