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What is e^x*e^(x+1)=e^2 ? The e is the natural number 2.718... not the variable e. My teacher doesn't give a lot of notes so I am not sure if I multiply the two exponents on the left side, being x*(x+1), or if i add them.

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$$e^x\times e^{x+1}=e^{x+x+1}=e^{2x+1}$$ If $e^x\times e^{x+1}=e^2$, then, by the above, $$2x+1=2\\ \implies \boxed{x=\dfrac{1}{2}=0.5}$$

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  • $\begingroup$ @IlaIsabelle Sure! $\endgroup$
    – user122283
    Apr 8 '14 at 22:25

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