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Statement: Let $X$ be a Banach space If $x_n \rightarrow x$ weakly and every subsequence of $\{x_n\}$ has a strongly convergent subsequence, then $x_n\rightarrow x$ strongly in $X$

Attempt: ?

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    $\begingroup$ Hint: If you can show that weak limit is unique, then the statement become: Every subsequence of $x_n$ has a subsequence converges strongly to $x$. $\endgroup$ – user99914 Apr 6 '14 at 4:55
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Suppose $\lim_{n \to \infty}x_n\neq x$. Then there is an $\epsilon \gt0$ and a subsequence $(x_{n_k})$ such that $\|x_{n_k}-x\|\ge\epsilon$ for all $k\in\mathbb{N}$. Use this to derive a contradiction.

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