I am having a problem finding the x intercepts.
I have found the Standard form of the Quadratic (Vertex form) -(x+2)^2 + 8 [by the way, does is matter if the 8 is in front of the minus sign or in the back?]
y intercept = (0,4)
To find the x intercept I did the following:
0 = -(x+2)^2+8
-8 = -(x+2)^2
(-8)/(-1) = (-(x+2)^2) / -1
8 = (x+2)^2
Square root both sides:
square root 2, square root 4 = x+2
Now this is where I am stuck
The answer key in the book states that the x intercept is +2, square root of 2 (minus) 2
and -2,-2 the square root of 2
Yet, after you simplify the radicals doesn't the 2 come directly out in front?
Other questions to clarify my understanding:
Do we not place the +/- in front of the simplified radical?
Does we not place the -2 in front of the + and - sign?
This is Pre-Calculus class, thus my algebra may be flawed. Please indicate what I am failing to understand. Please explain as if I am a 5 year old.
Thanks in advance.