Assume there are $2$ bins (bin $a$ and bin $b$ ), and each bin contains $n$ indistinguishable balls with $n>10$. The probability of picking $k$ ball from each bin is $p_k$, ($k\ge 0$). Then what is the probability of picking $4$ balls out from the two bins?
My try:
If $i$ balls are picked from bin $a$, then $4-i$ balls should be picked from bin $b$, with $0\le i\le 4$. Therefore, the probability of picking $4$ balls from the two bins is \begin{align*} &\Pr[\text{picking $4$ balls from the two bins}] \\ & = p_0\cdot p_4 + p_4\cdot p_0 \\ & + p_1\cdot p_3 + p_3\cdot p_1 \\ & + p_2\cdot p_2 \end{align*}
However, my classmate said my equation is not "symmetric", and he gave the probability as
\begin{align*} &\Pr[\text{picking $4$ balls from the two bins}] \\ & = p_0\cdot p_4 + p_4\cdot p_0 \\ & + p_1\cdot p_3 + p_3\cdot p_1 \\ & + p_2\cdot p_2 + \color{red}{ p_2\cdot p_2} \end{align*}
Which probability is right? If I am right, how do I convince him? Or did I miss something in my calculation?
Thanks in advance!