1
$\begingroup$

I have a few exam review questions that I don't know how to solve. Maybe someone can help me out.

Two hockey teams play a best-of-seven series (play until a team wins a total of 4 games)

Assume team A has a probability of 3/4 of beating team B.

Assume the results of the games are independent

What is the probability that all seven games will be played in the series

$\endgroup$

1 Answer 1

2
$\begingroup$

The series lasts $7$ games precisely if the first $6$ games are evenly split between the two teams. So we want the probability that Team A wins $3$ of the first $6$ games and loses $3$. The probability of that is $$\binom{6}{3}\left(\frac{3}{4}\right)^3\left(\frac{1}{4}\right)^3.$$

$\endgroup$

You must log in to answer this question.

Not the answer you're looking for? Browse other questions tagged .